150. Evaluate Reverse Polish Notation
by Botao Xiao
Question:
Evaluate the value of an arithmetic expression in Reverse Polish Notation. Valid operators are +, -, *, /. Each operand may be an integer or another expression. Note:
- Division between two integers should truncate toward zero.
- The given RPN expression is always valid. That means the expression would always evaluate to a result and there won’t be any divide by zero operation.
Example 1:
Input: ["2", "1", "+", "3", "*"]
Output: 9
Explanation: ((2 + 1) * 3) = 9
Example 2:
Input: ["4", "13", "5", "/", "+"]
Output: 6
Explanation: (4 + (13 / 5)) = 6
Example 3:
Input: ["10", "6", "9", "3", "+", "-11", "*", "/", "*", "17", "+", "5", "+"]
Output: 22
Explanation:
((10 * (6 / ((9 + 3) * -11))) + 17) + 5
= ((10 * (6 / (12 * -11))) + 17) + 5
= ((10 * (6 / -132)) + 17) + 5
= ((10 * 0) + 17) + 5
= (0 + 17) + 5
= 17 + 5
= 22
Thinking:
- Method1:
- 使用栈,如果遇到运算符则出栈两个数组再将结果入栈。
class Solution {
public int evalRPN(String[] tokens) {
if(tokens == null || tokens.length == 0) return 0;
if(tokens.length == 1) return Integer.parseInt(tokens[0]);
Stack<Integer> stack = new Stack<>();
int result = 0;
for(int i = 0; i < tokens.length; i++){
if(!isOper(tokens[i]))
stack.push(Integer.parseInt(tokens[i]));
else{
Integer b = stack.pop();
Integer a = stack.pop();
result = operation(a, b, tokens[i]);
stack.push(result);
}
}
return result;
}
public static boolean isOper(String s){
return s.equals("+") || s.equals("-") || s.equals("/") || s.equals("*");
}
private static int operation(Integer a, Integer b, String op){
if(op.equals("+")) return a + b;
else if(op.equals("-")) return a - b;
else if(op.equals("*")) return a * b;
else return a / b;
}
}
二刷
- 这道题已经是第三次写了,很明确就是使用栈。
- 对于一刷的时候有了优化,使用switch取代了冗余的if-else。
- 这次刷犯的错:加法和乘法是有交换律的,而减法和除法不遵从交换律,所以要注意pop出来的顺序。
class Solution { public int evalRPN(String[] tokens) { if(tokens == null || tokens.length == 0) return 0; Stack<Integer> stack = new Stack<>(); int opt1 = 0; int opt2 = 0; for(String token : tokens){ switch(token){ case "+": stack.push(stack.pop() + stack.pop()); break; case "-": opt1 = stack.pop(); opt2 = stack.pop(); stack.push(opt2 - opt1); break; case "*": stack.push(stack.pop() * stack.pop()); break; case "/": opt1 = stack.pop(); opt2 = stack.pop(); stack.push(opt2 / opt1); break; default: stack.push(Integer.parseInt(token)); break; } } return stack.peek(); } }
Subscribe via RSS