145. Binary Tree Postorder Traversal
by Botao Xiao
Question
Given a binary tree, return the postorder traversal of its nodes’ values.
Example:
Input: [1,null,2,3]
   1
    \
     2
    /
   3
Output: [3,2,1]
Thinking:
- Method : 递归 ```Java /**
- Definition for a binary tree node.
- public class TreeNode {
- int val;
- TreeNode left;
- TreeNode right;
- TreeNode(int x) { val = x; }
- }
 */
class Solution {
 public ListpostorderTraversal(TreeNode root) { List result = new ArrayList<>(); post(root, result); return result; } private void post(TreeNode root, List result){ if(root == null) return; post(root.left, result); post(root.right, result); result.add(root.val); } } ``` 
二刷
/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */
class Solution {
    public List<Integer> postorderTraversal(TreeNode root) {
        List<Integer> result = new LinkedList<>();
        post(root, result);
        return result;
    }
    private void post(TreeNode node, List<Integer> result){
        if(node == null) return;
        post(node.left, result);
        post(node.right, result);
        result.add(node.val);
    }
}
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