225. Implement Stack using Queues
by Botao Xiao
225. Implement Stack using Queues
Question
Implement the following operations of a stack using queues.
- push(x) – Push element x onto stack.
- pop() – Removes the element on top of the stack.
- top() – Get the top element.
- empty() – Return whether the stack is empty.
Example:
MyStack stack = new MyStack();
stack.push(1);
stack.push(2);
stack.top(); // returns 2
stack.pop(); // returns 2
stack.empty(); // returns false
Thinking:
- Method 1:通过linkedList实现
class MyStack {
LinkedList<Integer> list;
int count = 0;
/** Initialize your data structure here. */
public MyStack() {
list = new LinkedList<>();
}
/** Push element x onto stack. */
public void push(int x) {
list.add(x);
count++;
}
/** Removes the element on top of the stack and returns that element. */
public int pop() {
count --;
return list.pollLast();
}
/** Get the top element. */
public int top() {
return list.get(count - 1);
}
/** Returns whether the stack is empty. */
public boolean empty() {
return count == 0;
}
}
/**
* Your MyStack object will be instantiated and called as such:
* MyStack obj = new MyStack();
* obj.push(x);
* int param_2 = obj.pop();
* int param_3 = obj.top();
* boolean param_4 = obj.empty();
*/
二刷
- Use LinkedList to realize stack.
class MyStack { LinkedList<Integer> stack = null; int size = 0; /** Initialize your data structure here. */ public MyStack() { stack = new LinkedList<>(); } /** Push element x onto stack. */ public void push(int x) { this.stack.addFirst(x); this.size++; } /** Removes the element on top of the stack and returns that element. */ public int pop() { this.size --; return this.stack.pollFirst(); } /** Get the top element. */ public int top() { return this.stack.get(0); } /** Returns whether the stack is empty. */ public boolean empty() { return this.size == 0; } } /** * Your MyStack object will be instantiated and called as such: * MyStack obj = new MyStack(); * obj.push(x); * int param_2 = obj.pop(); * int param_3 = obj.top(); * boolean param_4 = obj.empty(); */
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