341. Flatten Nested List Iterator
by Botao Xiao
Question
Given a nested list of integers, implement an iterator to flatten it.
Each element is either an integer, or a list – whose elements may also be integers or other lists.
Example 1:
Input: [[1,1],2,[1,1]]
Output: [1,1,2,1,1]
Explanation: By calling next repeatedly until hasNext returns false,
the order of elements returned by next should be: [1,1,2,1,1].
Example 2:
Input: [1,[4,[6]]]
Output: [1,4,6]
Explanation: By calling next repeatedly until hasNext returns false,
the order of elements returned by next should be: [1,4,6].
Thinking:
- Method 1:
- 将链表添加进入的时候需要用到递归。
- 使用队列来装载数据。
/**
* // This is the interface that allows for creating nested lists.
* // You should not implement it, or speculate about its implementation
* public interface NestedInteger {
*
* // @return true if this NestedInteger holds a single integer, rather than a nested list.
* public boolean isInteger();
*
* // @return the single integer that this NestedInteger holds, if it holds a single integer
* // Return null if this NestedInteger holds a nested list
* public Integer getInteger();
*
* // @return the nested list that this NestedInteger holds, if it holds a nested list
* // Return null if this NestedInteger holds a single integer
* public List<NestedInteger> getList();
* }
*/
public class NestedIterator implements Iterator<Integer> {
private LinkedList<Integer> list;
public NestedIterator(List<NestedInteger> nestedList) {
this.list = new LinkedList<>();
addList(nestedList);
}
private void addList(List<NestedInteger> list){
for(NestedInteger num : list){
if(num.isInteger()){
this.list.add(num.getInteger());
}else
addList(num.getList());
}
}
@Override
public Integer next() {
return this.list.poll();
}
@Override
public boolean hasNext() {
return !this.list.isEmpty();
}
}
/**
* Your NestedIterator object will be instantiated and called as such:
* NestedIterator i = new NestedIterator(nestedList);
* while (i.hasNext()) v[f()] = i.next();
*/
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