771. Jewels and Stones

Question

You’re given strings J representing the types of stones that are jewels, and S representing the stones you have. Each character in S is a type of stone you have. You want to know how many of the stones you have are also jewels.

The letters in J are guaranteed distinct, and all characters in J and S are letters. Letters are case sensitive, so “a” is considered a different type of stone from “A”.

Example 1:

Input: J = "aA", S = "aAAbbbb"
Output: 3
Example 2:

Input: J = "z", S = "ZZ"
Output: 0

Note:

  • S and J will consist of letters and have length at most 50.
  • The characters in J are distinct.

Solution

  • Method 1: HashSet
    class Solution {
        public int numJewelsInStones(String J, String S) {
            Set<Character> set = new HashSet<>();
            for(char c : J.toCharArray()){
                set.add(c);
            }
            int res = 0;
            for(char c : S.toCharArray()){
                if(set.contains(c)) res++;
            }
            return res;
        }
    }
    

Amazon session

class Solution {
    public int numJewelsInStones(String J, String S) {
        Set<Character> jewels = new HashSet<>();
        for(char c : J.toCharArray()){
            jewels.add(c);
        }
        int result = 0;
        for(char c : S.toCharArray()){
            if(jewels.contains(c))
                result++;
        }
        return result;
    }
}